发布网友 发布时间:2022-04-22 00:19
共2个回答
热心网友 时间:2023-07-20 00:56
A = rand(2, 10); % 2*10
modA = hypot(A(1,:), A(2,:));
direction = pi/4; % "已知方向",这里假设方位角是π/4
D = [cos(direction); sin(direction)];
B = [modA*D(1); modA*D(2)]; % 2*10
热心网友 时间:2023-07-20 00:57
fliplr(a)